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raising the rear suspension
Hi Guys I have a 4pt, 99 model. an id like to raise the rear suspension a wee bit,,is their any dog bones out there that would do this,,or are they any bones from a different bike that would fit it... thanks...
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This piece costed me nearly 1000euro this summer. It broke the top attachement of the suspension and let the gas out. This happent on the way to mongolia.
New rear suspension from wilbers 400euro + express shipment to Ulaanbator 550euro. |
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Maybe, maybe not....
There is a lot of force in this connection. The swingarms ratio between the pivoting point , the full lenghs , and the fixation for the suspention is around 1:4 Lets say the rear wheel is under a 150kg load. 200kg bike + driver + lugage, divide between front and backwheel. This make a 600kg load on the rear spring, 4x150kg. Just standing still without moving... I dont think anything will break under normal driving, i broke my one driving to fast in kazachstan. |
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Mine has stood up to some pretty serious shit. I've taken motocross jumps, ridden shitty roads in Romania and Ukraine with foot-deep holes, and ridden offroad with panniers on.
I replaced the stock shock after over 100.000km. It worked fine, I just got an offer I couldnt resist on a Wilbers. |
Just to be clear
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In your example the force acting remains as 150Kg through a lever arm that would generate a bending moment if it were not for the fact that the swinging arm is jointed and unable to resist/generate a bending moment at it's fixing. I do agree that substantial forces, in motorcycle terms, are generated in a rear shock absorber; for instance impact loading can double a static force (in your example, 150 Kg static could generate a more or less instantaneous, temporary force of up to 300 Kg while hitting the ground after jumping a bike). |
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Hi Dave
This is the calculation i did, i know it over simplified but it is just to give an idea of the static forces involved. F1=Rearwheel F2=Damper |
the top fixation point didn't break of completely. It just got slightly bended which made a crack in the top of the damper and the gas escaped.
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Now I see what you were saying in your earlier post: I've just measured my XT225 swingarm, not exactly but near enough for this discussion. The L1 to L2 ratio I have is 510/150 = 3.4 so I agree with you about the increased force acting through the shock; in my case increased by a factor of 3.4 or thereabouts. For the dynamic forces produced in the shock, these should be much less than the theoretical maximum effect of doubling that I mentioned so long as the shock is doing it's job, but they would be worse than normally occurs if a shock absorber is not working properly. |
I dont get this, where do you add the tire, spring and shock in this?
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The green triangle represents the fixing point of the swing arm - a pivot point for the black horizontal line which is the swinging arm. The blue and red force arrows represent the action of the wheel and the shock absorber with respect to the swinging arm; now I look at it again, one of those force arrowheads needs to act in the opposite direction to the other for equilibrium purposes. Hope that helps. |
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Sorry the diagram is for a Australian XT driver doh (Upside Down) , |
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